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\[1\star \]

A square-shaped loop with surface area
0.2 m2
is placed in a uniform magnetic field with intensity
0.3 T
and the angle between the field and the loop's surface is
600
The magnetic flux equals

\[\phi=0.015\;\;T.m^2\;\;\;\;\;\;-C\]

\[\phi=0.03\;\;T.m^2\;\;\;\;\;\;-A\]

\[\phi=0.06\;\;T.m^2\;\;\;\;\;\;-D\]

\[\phi=0.052\;\;T.m^2;\;\;\;\;\;-B\]

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    \[2\star \]

    A square-shaped loop is inserted into a uniform magnetic field as shown in figure \[A\] where the angle between the field and the normal to the surface is 20 degrees and the magnetic flux was calculated to be
    0.5 T.m2
    The loop's position was adjusted so that the magnetic field became perpendicular to the surface as in figure \[B\] The magnetic flux value then becomes

    \[\phi=0.015\;\;T.m^2\;\;\;\;\;\;-C\]

    \[\phi=0.03\;\;T.m^2\;\;\;\;\;\;-A\]

    \[\phi=0.06\;\;T.m^2\;\;\;\;\;\;-D\]

    \[\phi=0.052\;\;T.m^2;\;\;\;\;\;-B\]

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    \[3\star \star\]

    One of the following loops generates a clockwise induced current when viewed from above the loop

    Moving the magnet away from the loop -C

    Moving the magnet towards the loop -A

    Bringing the loop closer to a current-carrying wire -D\

    Moving the loop away from a current-carrying wire -B

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    \[4\star \]

    A loop connected to a battery carries a direct current, forming a magnetic field as shown in the figure below. At the moment a magnet is brought close to the loop, one of the following occurs during the approach

    Current intensity increases -C

    Current intensity decreases -A

    Current intensity becomes zero -D

    Current intensity remains the same -B

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    \[5\star\star \]

    In the opposite figure, there are two coils: the first is connected to a battery and a variable resistor, wound around an iron core, and the second is connected only to a resistor. An induced current is obtained in the second coil and passes through the resistor from \[B\Rightarrow A\] inside the resistor in one of the following cases:

    Opening the switch in the first coil - C

    Removing the iron core from the first coil - A

    Decreasing the variable resistor in the first coil - D

    Increasing the variable resistor in the first coil - B

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    \[6\star \]

    A flexible loop placed inside a uniform magnetic field as shown in the figure. It is possible to generate an induced current in the loop clockwise when:

    Removing the loop from the field - C

    Moving the loop within the field - A

    Rotating it parallel to the page - D

    Expanding the loop - B

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    \[7\star\star \]


    A circular loop with radius
    0.2 m
    placed perpendicular to a changing magnetic field according to the function:
    B= 0.3 t3 +2t
    The magnitude of the induced potential difference in the loop at the third second equals:

    \[\Delta V_{ind}=-3.16\;\; V\;\;\;\;\;\;-C\]

    \[\Delta V_{ind}=-1.27\;\; V\;\;\;\;\;\;-A\]

    \[\Delta V_{ind}=-1.38\;\; V\;\;\;\;\;\;-D\]

    \[\Delta V_{ind}=-2.08\;\; V\;\;\;\;\;-B\]

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    \[8\star \]

    A flexible loop with variable area is exposed to a magnetic field of strength
    0.5 × 10–4 T
    and perpendicular to the surface area. If its surface area increases by
    0.1 m2
    during a time of
    0.4 s
    then the average induced potential difference in the loop equals:

    \[\Delta V_{ind}=1.25 \times 10^{-5}\;\; V\;\;\;\;\;\;-C\]

    \[\Delta V_{ind}=1.11 \times 10^{-5}\;\; V\;\;\;\;\;\;-A\]

    \[\Delta V_{ind}=2.24 \times 10^{-5}\;\; V\;\;\;\;\;\;-D\]

    \[\Delta V_{ind}=4.35 \times 10^{-5}\;\; V\;\;\;\;\;-B\]

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    \[9\star\star \]

    A rotatable loop around its axis with surface area
    0.1 m2
    placed in a uniform magnetic field of strength
    0.2 T
    with its surface parallel to the field. It starts rotating around its axis by an external force with an angular velocity of
    5 Rad /s
    The induced potential difference at the fourth second equals:

    \[\Delta V_{ind}=0.06\;\; V\;\;\;\;\;\;-C\]

    \[\Delta V_{ind}=0.09\;\; V\;\;\;\;\;\;-A\]

    \[\Delta V_{ind}=0.02\;\; V\;\;\;\;\;\;-D\]

    \[\Delta V_{ind}=0.05\;\; V\;\;\;\;\;-B\]

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    \[10\star \]

    A solenoid with cross-sectional area
    0.2 m2
    air core and 50 turns and length
    10 Cm
    carries a current of \[3A\] The flux passing through the surface of the solenoid is: >

    \[\phi= 3.77 \times 10^{-4}\;\;T.m^2\;\;\;\;\;\;-C\]

    \[\phi= 6.0 \times 10^{-4}\;\;T.m^2\;\;\;\;\;\;-A\]

    \[\phi= 3.0 \times 10^{-2}\;\;T.m^2\;\;\;\;\;\;-D\]

    \[\phi= 1.5 \times 10^{-3}\;\;T.m^2;\;\;\;\;\;-B\]

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    \[11\star \]

    A solenoid with self-inductance coefficient \[0.1\;H\] connected to a battery with current \[2\;A\] flowing through it. The current direction was reversed during a time period of \[0.15\;S\]. The induced electromotive force generated in the solenoid is

    \[\Delta V_{ind}=-1.9\;\; V\;\;\;\;\;\;-C\]

    \[\Delta V_{ind}=0.0\;\; V\;\;\;\;\;\;-A\]

    \[\Delta V_{ind}=2.7\;\; V\;\;\;\;\;\;-D\]

    \[\Delta V_{ind}=1.3\;\; V\;\;\;\;\;-B\]
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    \[12\star\star\star \]

    A helicopter with aluminum blades of length
    8 m
    flies horizontally over the United Arab Emirates in a magnetic field region with strength
    0.4 × 10–4 T
    and rotates with an angular velocity of
    200 rad/s
    The induced potential difference generated from the axis to the end of the blade equals

    \[\Delta V_{ind}=0.032\;\; V\;\;\;\;\;\;-C\]

    \[\Delta V_{ind}=0.254\;\; V\;\;\;\;\;\;-A\]

    \[\Delta V_{ind}=0.128\;\; V\;\;\;\;\;\;-D\]

    \[\Delta V_{ind}=0.064\;\; V\;\;\;\;\;-B\]

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    \[13\star\star \]

    A coil rotates in a magnetic field with a constant rate and its axis perpendicular to the field. The number of turns is 20. When the relationship between flux and time was plotted, the following graph was produced. The maximum induced potential difference in the coil equals

    \[\Delta V_{max}=6.7\;\; V\;\;\;\;\;\;-C\]

    \[\Delta V_{max}=5.3\;\; V\;\;\;\;\;\;-A\]

    \[\Delta V_{max}=0.79\;\; V\;\;\;\;\;\;-D\]

    \[\Delta V_{max}=4.2\;\; V\;\;\;\;\;-B\]

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    \[14\star \]

    A primary coil with 30 turns is connected to a battery. When the switch is closed, the current in the primary coil becomes \[ 3\;A\] after a time of \[0.1\;S\] and the mutual inductance is \[0.2\;H\]. If the number of turns in the secondary coil is half that of the primary coil, the rate of change of flux in the secondary coil equals

    \[\frac{\Delta \emptyset}{\Delta t}=0.6\;\; V\;\;\;\;\;\;-C\]

    \[\frac{\Delta \emptyset}{\Delta t}=0.4\;\; V\;\;\;\;\;\;-A\]

    \[\frac{\Delta \emptyset}{\Delta t}=0.3\;\; V\;\;\;\;\;\;-D\]

    \[\frac{\Delta \emptyset}{\Delta t}=0.15\;\; V\;\;\;\;\;-B\]

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    \[15\star \]

    A conducting wire of length \[0.2 \;m\] is moved to cut magnetic field lines with a velocity perpendicular to the field of magnitude \[20\; m/S\] on a frictionless track connected to a resistor of \[5\; Ω \]. If the magnetic field strength is \[B=0.2\;T\], then the induced current in the resistor equals

    \[I_{ind}=1\;\; A\;\;\;\;\;\;-C\]

    \[I_{ind}=0.48\;\; A\;\;\;\;\;\;-A\]

    \[I_{ind}=0.3\;\; A\;\;\;\;\;\;-D\]

    \[I_{ind}=0.16\;\; A\;\;\;\;\;-B\]

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    \[16\star\star\star \]

    A coil rotates in a magnetic field with its rotation axis perpendicular to the field. The number of turns is 30. The relationship between induced potential difference and time was plotted, resulting in the following graph. The magnetic flux passing through one turn at the fourth second equals

    \[\phi= 0.0\;\;\;\;\;\;-C\]

    \[\phi= - 0.054\;\;T.m^2\;\;\;\;\;\;-A\]

    \[\phi= 0.24 \;\;T.m^2\;\;\;\;\;\;-D\]

    \[\phi= - 0.085 \;\;T.m^2;\;\;\;\;\;-B\]

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    \[17\star\star \]

    Two rings, one made of wood and the other of aluminum, were placed on the ground as shown in the figure. Two identical magnets were dropped vertically from the same height to fall freely. One of the following answers is correct (neglecting air resistance)

    The magnet falling on the wooden ring arrives first -C

    Both magnets reach the ground at the same time -A

    Cannot be determined until we know the mass of the falling magnets -D

    The magnet falling on the aluminum ring arrives first -B

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    \[18\star \]

    A magnet was moved at a speed towards a fixed solenoid connected to a galvanometer, which led to the generation of an induced potential difference and induced current. If the speed of the magnet's approach to the coil is doubled, then one of the following answers is incorrect.

    The intensity of the induced current increases -C

    The flux on the coil increases -A

    The galvanometer's deflection increases -D

    The induced potential difference increases -B

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    \[19\star \].

    Two lamps \[B2 \;\;\;\;\;and\;\;\;\;\; B1\] The first is connected to a resistor and the second is connected to a coil as shown in the figure. When the switch \[S\] is closed immediately, the lamp that lights up first is

    Both lamps do not light up -C

    ( B2 ) The lamp lights up first -A

    Both lamps light up immediately -D

    ( B1 ) The lamp lights up first -B

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    \[20\star\star \]

    A coil consists of 20 turns with a self-inductance coefficient \[0.4\; H \] 8 turns were cut from the coil, then the self-inductance coefficient for the eight turns equals

    \[L=0.24\;\;H\;\;\;\;\;\;-C\]

    \[L=0.32\;\;H\;\;\;\;\;\;-A\]

    \[L=0.16\;\;H\;\;\;\;\;\;-D\]

    \[L=0.22\;\;H\;\;\;\;\;-B\]

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    \[21\star\star \]

    A solenoid with its length, number of turns, and cross-sectional area \[L=0.2\;m\;\;\;\;\;\;\;\; N=60\;\;\;\;\;\;\;\;A=0.1\;m^2\] and a current passes through it at a constant rate
    A wire was wound in the form of a small solenoid around the previous solenoid with its length, number of turns, and cross-sectional area \[L=0.05\;m\;\;\;\;\;\;\;\; N=6\;\;\;\;\;\;\;\;A=0.15\;m^2\] Then the mutual inductance coefficient between the two coils equals

    \[M=6.32 \times 10^{-4}\;\;H\;\;\;\;\;\;-C\]

    \[M=5.32 \times 10^{-4}\;\;H\;\;\;\;\;\;-A\]

    \[M=1.45 \times 10^{-4}\;\;H\;\;\;\;\;\;-D\]

    \[M=2.26 \times 10^{-4}\;\;H\;\;\;\;\;-B\]

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    \[22\star\star \]

    A coil connected to a closed circuit changes the flux passing through it due to a change in the current passing through it according to the following graph

    One of the following graphs represents the relationship between the induced potential difference and time for this coil

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    \[23\star \]

    The following graph shows the relationship between the change in magnetic flux on the coil and time
    Then the induced potential difference in the coil is zero in the stage

    \[C \Longrightarrow D\;\;\;\;\;\;-C\]

    \[A \Longrightarrow B\;\;\;\;\;\;-A\]

    \[E \Longrightarrow F\;\;\;\;\;\;-D\]

    \[B \Longrightarrow C\;\;\;\;\;-B\]

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    \[24\star\star \]

    In the figure below, a permanent magnet rod is pulled upward at a constant speed through a wire loop
    Which of the following best describes the direction(s) of the induced current in the loop (viewed from above the loop)

    First clockwise, then counterclockwise -C

    Always clockwise -A

    First counterclockwise, then clockwise -D

    Always counterclockwise -B

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    \[25\star\star \]

    A file contains 50 square-shaped loops with side length \[10\;Cm\] The file is placed in a magnetic field perpendicular to the surface and the field changes at a rate of \[ 6 \frac{T}{S}\] The induced potential difference equals

    \[\Delta V_{ind}=4\;\; V\;\;\;\;\;\;-C\]

    \[\Delta V_{ind}=2\;\; V\;\;\;\;\;\;-A\]

    \[\Delta V_{ind}=6\;\; V\;\;\;\;\;\;-D\]

    \[\Delta V_{ind}=3\;\; V\;\;\;\;\;-B\]

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    \[26\star \]

    A metal loop connected to a rod swings freely like a pendulum (neglecting air resistance) A magnetic field was applied as shown in figure A. It was observed that the pendulum stopped moving after some time. Then the field direction was changed to be parallel to the loop's motion as shown in figure B. In figure B, the pendulum will:

    The pendulum continues swinging for a slightly longer time - C

    The pendulum continues swinging for the same time period - A

    The pendulum continues swinging without stopping - D

    The pendulum continues swinging for a slightly shorter time - B

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    \[27\star \]

    When a conducting wire moves in one of the directions shown in the figure below, an induced potential difference is generated between the ends of the wire

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    \[28\star \]

    A conducting wire of length \[L\] is fixed at one end and the other end rotates with uniform angular velocity \[W\] so that the wire cuts through uniform field lines \[B\] perpendicular to the wire's length. The expression for the induced potential difference is

    \[∆𝑉_{𝑖𝑛𝑑} = B . W .\frac{L^2}{2}\;\;\;\;\;\;-C\]

    \[∆𝑉_{𝑖𝑛𝑑} = B . W .\frac{L}{2}\;\;\;\;\;\;-A\]

    \[∆𝑉_{𝑖𝑛𝑑} = B . W .\frac{3L^2}{4}\;\;\;\;\;\;-D\]

    \[∆𝑉_{𝑖𝑛𝑑} = B . W .L\;\;\;\;\;-B\]

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    \[29\star\star\star \]

    A square loop with side length (5 cm) \[5\;cm\] is placed at the edge of a uniform magnetic field with intensity \[B=0.6\;T\] It enters the field with a constant speed of \[1\;cm/S\] and travels a distance of \[20\;cm\] completely exiting the field

    One of the graphs correctly represents the relationship between the induced potential difference and time
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    \[30\star\star \]

    A coil with self-inductance \[L\]
    has current changing over time according to the following diagram

    One of the graphs represents the induced potential difference over time for the coil
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    \[31\star\star \]

    A coil with 30 turns
    The following graph
    shows the relationship between the change in magnetic flux through the coil and time
    Using the graph below the average induced potential difference in the coil during phase \[C\Rightarrow D\] equals

    \[\Delta V_{ind}=-0.8\;\; V\;\;\;\;\;\;-C\]

    \[\Delta V_{ind}=1.2\;\; V\;\;\;\;\;\;-A\]

    \[\Delta V_{ind}=0.8\;\; V\;\;\;\;\;\;-D\]

    \[\Delta V_{ind}=-1.2\;\; V\;\;\;\;\;-B\]

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    \[32\star\star \]

    A student wanted to generate an induced current in a loop so that the current flows clockwise in the loop
    while looking at the loop from the left side, he had to move the magnet in the direction

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    \[33\star\star \]

    An induced electric current is generated in the loop in the direction shown in the figure below clockwise when moving the loop towards the axis

    \[ Y^+ \uparrow \;\;\;\;\;\;-C\]

    \[X^+ \longrightarrow \;\;\;\;\;\;-A\]

    \[Y^- \downarrow \;\;\;\;\;\;-D\]

    \[X^- \longleftarrow \;\;\;\;\;-B\]

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    \[34\star\star \]

    When moving the straight magnet in the direction shown in the adjacent figure, the direction of the induced current generated in the two coils \[A\;\;\;\;\;and\;\;\;\;\;B\] which passes through the galvanometer in order

    From D to C in coil A, from X to Y in coil B - C

    From C to D in coil A, from X to Y in coil B - A

    From D to C in coil A, from Y to X in coil B - D

    From C to D in coil A, from Y to X in coil B - B
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    \[35\star \]

    A coil rotates in a magnetic field and is connected through half rings to a resistor
    Then one of the following figures represents the instantaneous induced current passing through the resistor

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    \[36\star \]

    A coil rotates in a magnetic field and is connected through two rings to a resistor. One of the following figures
    represents the instantaneous induced current passing through the resistor

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    \[37\star \]

    A coil rotates clockwise in a magnetic field and is connected through two rings to a resistor where the wire \[CD\]
    is connected to the outer ring (orange ring) and the wire \[BA\] is connected to the inner ring (green ring)
    Then one of the following figures correctly represents the direction of the current in the external circuit

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    \[38\star \]

    A solenoid carrying current had its magnetic field calculated at a point on its axis, resulting in field strength
    B = 0.05 T
    The current was doubled and the loops were brought closer together until the solenoid length became half of its original value. The magnetic field strength at any point on the solenoid's axis becomes:

    \[B=0.025 \;\;T\;\;\;\;\;\;-C\]

    \[B=0.05 \;\;T\;\;\;\;\;\;-A\]

    \[B=0.1 \;\;T\;\;\;\;\;\;-D\]

    \[B=0.2 \;\;T\;\;\;\;\;\;-B\]

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    Answer the following questions

    \[1\star \]

    Based on electromagnetic induction phenomenon What happens to the lamp's brightness when bringing the magnet closer to the coil Explain the reason

    \[..........................................\;\;\;\;\;\;........................................\] \[..........................................\;\;\;\;\;\;........................................\] \[..........................................\;\;\;\;\;\;........................................\] \[..........................................\;\;\;\;\;\;........................................\]
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    • \[2\star \]

    Based on mutual electromagnetic induction phenomenon between two circuits, what happens to the lamp's brightness when opening the switch in the first circuit Explain the reason

    \[..........................................\;\;\;\;\;\;........................................\] \[..........................................\;\;\;\;\;\;........................................\] \[..........................................\;\;\;\;\;\;........................................\] \[..........................................\;\;\;\;\;\;........................................\]
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    • \[3\star \]

    In the following figure, a uniform magnetic field moves a coil from left to right at constant speed starting its motion from outside the field Determine at which positions a clockwise induced current is generated and explain the reason

    \[..........................................\;\;\;\;\;\;........................................\] \[..........................................\;\;\;\;\;\;........................................\] \[..........................................\;\;\;\;\;\;........................................\] \[..........................................\;\;\;\;\;\;........................................\] Determine at which positions no induced current will be generated and explain the reason \[..........................................\;\;\;\;\;\;........................................\] \[..........................................\;\;\;\;\;\;........................................\] \[..........................................\;\;\;\;\;\;........................................\] \[..........................................\;\;\;\;\;\;........................................\]
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    • \[4\star \]

    Based on the figures below, complete the table data

    Figure 2

    Figure 1

    Device Number

    \[.................\]

    \[.................\]

    Device Name

    \[.................\]

    \[.................\]

    Rotation Direction Relative to Clock

    \[.................\]

    \[.................\]

    Works Based on Phenomenon

    \[.................\]

    \[.................\]

    Function of Half Rings

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    • \[5\star \]

    In electromagnetic induction phenomenon, move a conducting wire that is part of a closed circuit inside a magnetic field and an induced current is generated as shown in the figure its direction is shown in the figure

    Determine the positive and negative poles of the wire \[A................\]\[B................\] Direction of induced current inside the wire from \[...............\Rightarrow ...............\] Using the three-finger rule, determine the magnetic field direction in the drawing
    During wire movement, an induced electromotive force was generated in the wire with value \[V_{ind}=0.15 \;V\]If the wire length is \[L=0.2\;m\]and the wire moves at speed \[V=3\;m/s\]calculate the minimum field strength that created this induced electromotive force \[..........................................\;\;\;\;\;\;........................................\] \[..........................................\;\;\;\;\;\;........................................\] \[..........................................\;\;\;\;\;\;........................................\] \[..........................................\;\;\;\;\;\;........................................\]
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    • \[6\star \]

    In the figure below, a solenoid connected to a battery when switch \[s\]is closed, the current intensity became \[I=10\;A\]after time \[t=0.1\;s\]an induced force was generated in the coil with value \[∆𝑉_{𝑖𝑛𝑑}=-2\;V\]

    Calculate the self-inductance coefficient of the coil \[..........................................\;\;\;\;\;\;........................................\] \[..........................................\;\;\;\;\;\;........................................\] \[..........................................\;\;\;\;\;\;........................................\] Calculate the flux passing through each turn of the coil \[..........................................\;\;\;\;\;\;........................................\] \[..........................................\;\;\;\;\;\;........................................\] \[..........................................\;\;\;\;\;\;........................................\] Discuss the validity of this statement: Ahmed said that the self-inductance coefficient of the coil cannot be negative \[..........................................\;\;\;\;\;\;........................................\] \[..........................................\;\;\;\;\;\;........................................\]
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