Electric Field and Gauss's Law Question Bank |
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1
One of the following measurement units is equivalent to the electric field measurement unit
\[Kg.m.A^{-1}.s^{-2}\;\;\;\;\;\;-C\]
\[Kg.m.A^{-1}.s^{-3}\;\;\;\;\;\;-A\]
\[Kg.m.A^{-1}.s^{-1}\;\;\;\;\;\;-D\]
\[Kg.m.A^{-2}.s^{-2}\;\;\;\;\;\;-B\]
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2
An electric field with intensity \[E=500\frac{N}{C}\] has an electron placed inside it. The electric force acting on the electron equals:
\[q_e=1.6×10^{-19}C\]

\[Fe=4×10^{-17} \;\;N\;\;\;\;\;\;-C\]
Opposite to the field direction
\[Fe=4×10^{-17} \;\;N\;\;\;\;\;\;-A\]
In the field direction
\[Fe=8×10^{-17} \;\;N\;\;\;\;\;\;-D\]
Opposite to the field direction
\[Fe=8×10^{-17} \;\;N\;\;\;\;\;\;-B\]
In the field direction
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3
In the figure below, two charges are on the same line \[q_1=+9\;\;nc\;\;\;\;\;\;\;\;q_2=?\] At point \[A\]
the electric field is canceled. The magnitude and type of charge
\[q_2\] equals

\[q_2= - 3.2 ×10^{-7}\;\;c\;\;\;\;\;\;-C\]
\[q_2= + 1.44 ×10^{-7}\;\;c\;\;\;\;\;\;-A\]
\[q_2= -4.5 ×10^{-7}\;\;c;\;\;\;\;\;-D\]
\[q_2= + 2.25 ×10^{-7}\;\;c\;\;\;\;\;\;-B\]
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4
In the figure below, the field at point \[A\] was calculated
\[E_{net}=500\frac{N}{C}\]
and its direction is shown in the drawing. If the magnitude of the electric field
produced by the first charge equals
\[E_{1}=300\frac{N}{C}\]then the type
and magnitude of the second charge equals

\[q_2= - 3.24 ×10^{-9}\;\;c\;\;\;\;\;\;-C\]
\[q_2= - 2.43 ×10^{-9}\;\;c\;\;\;\;\;\;-A\]
\[q_2= + 1.78 ×10^{-9}\;\;c;\;\;\;\;\;-D\]
\[q_2= + 5.67 ×10^{-9}\;\;c\;\;\;\;\;\;-B\]
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5
In the figure below, the field lines for three charges are drawn.
One of the following answers is correct

\[q_1(-)\;\;\;\;q_2(+)\;\;\;\;q_3(+) \;\;\;\;\;q_3>q_1>q_2\;\;\;\;\;\;-C\]
\[q_1(+)\;\;\;\;q_2(-)\;\;\;\;q_3(-)\;\;\;\;\;q_1=q_2=q_3\;\;\;\;\;\;-A\]
\[q_1(+)\;\;\;\;q_2(-)\;\;\;\;q_3(-) \;\;\;\;\;q_1>q_2=q_3\;\;\;\;\;\;-D\]
\[q_1(+)\;\;\;\;q_2(-)\;\;\;\;q_3(-)\;\;\;\;\;q_2>q_1>q_3\;\;\;\;\;\;-B\]
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6
(1 ×10-10m ) A dipole with distance between its poles
( 0.4 m ) The field produced by the dipole was calculated at a point distant from the center of the dipole and along the dipole axis
The field intensity was \[E= 9×10^{-18}\frac{N}{C}\]then the dipole charge equals

\[q= 3.2 ×10^{-19}\;\;c\;\;\;\;\;\;-C\]
\[q= 2.6 ×10^{-19}\;\;c\;\;\;\;\;\;-A\]
\[q= 1.3 ×10^{-19}\;\;c;\;\;\;\;\;-D\]
\[q= 6.4 ×10^{-19}\;\;c\;\;\;\;\;\;-B\]
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7
A positively charged particle is placed inside the field shown in the figure below. One of the following answers represents the motion of the particle:
The particle moves with - C
increasing acceleration
The particle moves with - A
constant velocity
The particle moves with - D
decreasing acceleration
The particle moves with - B
constant acceleration
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8

A ball with mass (5g) is dropped to the ground while charged with a charge of (5 µc). The uniform electric field vector that makes it balanced is:
\[E= 1×10^3 \;\;N/C\;\;\;\;\downarrow\;\;\;\;\;\;-C\]
Downward
\[E= 9.8×10^3 \;\;N/C\;\;\;\;\downarrow\;\;\;\;\;\;-A\]
Downward
\[E= 1×10^3 \;\;N/C\;\;\;\;\uparrow\;\;\;\;\;\;-D\]
Upward
\[E= 9.8×10^3 \;\;N/C\;\;\;\;\uparrow\;\;\;\;\;\;-B\]
Upward
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9

An electron is projected into a uniform electric field with intensity (E= 1 × 103N/C)
directed towards the positive vertical axis as shown in the figure below
with a speed of (𝜗=5 × 106m/s) horizontally
and travels a horizontal distance of (8 cm).
In the same time period, it will have a vertical displacement of:

\[ ∆𝑌= 0.011 \;\;m\;\;\;\;\;\;-C\]
\[ ∆𝑌= 0.033 \;\;m\;\;\;\;\;\;-A\]
\[ ∆𝑌= 0.044 \;\;m\;\;\;\;\;\;-D\]
\[ ∆𝑌= 0.022\;\;m\;\;\;\;\;\;-B\]
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10
One of the following shapes has zero torque for an electric dipole in a uniform electric field

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11
( τ= 1.5 × 10-9N.m ) An electric dipole has maximum torque when
(positive z-axis) and is directed along the
(positive y-axis) in a uniform electric field directed along the
( E = 1 × 10-3N/C ) with magnitude

\[P=1.5×10^{-6} \;\;c.m\;\;\;\;\;\;-C\]
along the positive horizontal axis
\[ P=1.5×10^{-8} \;\;c.m\;\;\;\;\;\;-A\]
along the positive horizontal axis
\[P=1.5×10^{-8} \;\;c.m\;\;\;\;\;\;-D\]
along the negative horizontal axis
\[P=1.5×10^{-6} \;\;c.m\;\;\;\;\;\;-B\]
along the negative horizontal axis
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12

(0.3 m) An infinite wire has an electric field calculated at a point
( 2.5 × 103N/C ) The electric field magnitude was
and direction is shown in the figure. The number of electrons gained or lost per unit length equals

\[n=2.6×10^{11}\;\;\;\;\;\;-C\]
Gained electrons
\[ n=2.6×10^{11} \;\;\;\;\;\;-A\]
Lost electrons
\[n=3.4×10^{11}\;\;\;\;\;\;-D\]
Gained electrons
\[n=3.4×10^{11}\;\;\;\;\;\;-B\]
Lost electrons
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13

One of the following units is a unit of electric flux
\[Kg.m .A^{-1}.S^{-3}\;\;\;\;\;\;-C\]
\[Kg.m^2 .A^{-1}.S^{-3}\;\;\;\;\;\;-A\]
\[Kg.m^3 .A^{-1}.S^{-3}\;\;\;\;\;\;-D\]
\[Kg.m^2 .A^{-1}.S^{-2}\;\;\;\;\;\;-B\]
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14
A spherical shell is charged with a charge of
\[-4\;\;µc\] and a charge is placed inside it
\[+4\;\;µc\]>then the internal charge
\[q_1=?\]
and external charge of the spherical shell \[q_2=?\]
respectively

\[q_1=+4\;µc \;\;\;\;\;q_2=+4\;µc\;\;\;\;\;\;-C\]
\[q_1=0.0 \;\;\;\;\;q_2=0.0\;\;\;\;\;\;-A\]
\[q_1=-4\;µc \;\;\;\;\;q_2=0.0\;\;\;\;\;\;-D\]
\[q_1=-4\;µc \;\;\;\;\;q_2=+4\;µc\;\;\;\;\;\;-B\]
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15

( A ) Two infinite wires in length with charge densities and dimensions shown in the figure below. The point has a field intensity equal to

\[ E= 4200 \;\;N/C\;\;\;\;\;\longrightarrow\;\;\;\;\;\;-C\]
To the right
\[ E= 2800 \;\;N/C\;\;\;\;\;\longleftarrow \;\;\;\;\;\;-A\]
To the left
\[E= 4800 \;\;N/C\;\;\;\;\;\longrightarrow\;\;\;\;\;\;-D\]
To the right
\[E= 3500 \;\;N/C\;\;\;\;\;\longleftarrow\;\;\;\;\;\;-B\]
To the left
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16
Two infinite parallel conducting plates charged with equal charge density.
One of the following answers is correct:

\[ EA=EB=EC=ED \;\;\;\;\;\;-C\]
\[EA=EC=0 \;\;\;\;\;, \;\;\;\;\;EB=ED≠0\;\;\;\;\;\;-A\]
\[ EA=EB \;\;\;\;\;, \;\;\;\;\;ED=EC\;\;\;\;\;\;-D\]
\[EA>EC \;\;\;\;\;, \;\;\;\;\;EB=ED \;\;\;\;\;\;-B\]
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17

Two infinite unconnected plates with the same charge.
The electric field at point A was calculated to be \[E= 1×10^3\frac{N}{C}\]. The charge density on each plate is:

\[𝛿= 3.6 ×10^{-9} \;\;c/m^2\;\;\;\;\;\;-C\]
\[𝛿= 3.9×10^{-8} \;\;c/m^2\;\;\;\;\;\;-A\]
\[𝛿= 4.8×10^{-9} \;\;c/m^2\;\;\;\;\;\;-D\]
\[𝛿= 8.85×10^{-9} \;\;c/m^2\;\;\;\;\;\;-B\]
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17

Two infinite unconnected plates with the same charge.
The electric field at point A was calculated to be \[E= 1×10^3\frac{N}{C}\]. The charge density on each plate is:

\[𝛿= 3.6 ×10^{-9} \;\;c/m^2\;\;\;\;\;\;-C\]
\[𝛿= 3.9×10^{-8} \;\;c/m^2\;\;\;\;\;\;-A\]
\[𝛿= 4.8×10^{-9} \;\;c/m^2\;\;\;\;\;\;-D\]
\[𝛿= 8.85×10^{-9} \;\;c/m^2\;\;\;\;\;\;-B\]
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18

An infinite conducting plate with a charge density of
\[6 × 10^{-6} \;\;C/m^2\] was left.
A positively charged sphere with a charge of
\[+4\;\;nc\] and a mass of
\[9 \;\;g\] falls towards the plate.
The sphere moves with an acceleration of

\[ a=6.37 \;\;m/s^2\;\;\;\;\;\uparrow \;\;\;\;\;\;-C\]
Upwards
\[ a=3.92 \;\;m/s^2\;\;\;\;\;\uparrow \;\;\;\;\;\;-A\]
Upwards
\[a=4.52 \;\;m/s^2\;\;\;\;\;\downarrow \;\;\;\;\;\;-D\]
Downwards
\[a=9.48 \;\;m/s^2\;\;\;\;\;\downarrow \;\;\;\;\;\;-B\]
Downwards
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19


An uncharged spherical shell with an inner radius
\[0.5\;] and an outer radius
\[0.7\; m\] A point charge was placed inside it as shown in the figure below with a magnitude of
\[-6\;µc \] at its center. The electric field intensity at a point located at a distance of
\[0.6\; m \]

\[ E=0.0\;\;\;\;\;\;-C\]
\[ E = 2.3 ×10^5 \;\;N/C \;\;\;\;\;\;-A\]
\[ E = 1.5 ×10^5 \;\;N/C\;\;\;\;\;\;-D\]
\[ E = 4.6 ×10^5 \;\;N/C\;\;\;\;\;\;-B\]
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20

The relationship between the electric field and the distance from the surface of a hollow conducting sphere was plotted, resulting in the following graph. The conductor is charged with a charge of

\[q= 1.34×10^{-19} \;\;c\;\;\;\;\;\;-C\]
\[ q= 2.56×10^{-19} \;\;c\;\;\;\;\;\;-A\]
\[q= 2.14×10^{-19} \;\;c\;\;\;\;\;\;-D\]
\[q= 1.78×10^{-19} \;\;c\;\;\;\;\;\;-B\]
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21


The relationship between the electric field and the distance from the center of a charged sphere
with a non-conducting solid was plotted, resulting in the following graph. The magnitude of the electric field at
a point located at a distance
\[0.15\;m\] from the center of the sphere is equivalent to

\[E=2800 \;\;N/C\;\;\;\;\;\;-C\]
\[E=3000 \;\;N/C\;\;\;\;\;\;-A\]
\[E=2700 \;\;N/C\;\;\;\;\;\;-D\]
\[E=2900 \;\;N/C\;\;\;\;\;\;-B\]
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22


The relationship between the electric field and distance from the center
of a uniformly charged solid non-conducting sphere was plotted,
resulting in the following graph.
The amount of charge contained within a radius of
\[0.1\;m\]
of the sphere is equivalent to:

\[q= 2.2×10^{-9} \;\;c\;\;\;\;\;\;-C\]
\[ q= 2.45×10^{-9} \;\;c\;\;\;\;\;\;-A\]
\[q= 7.45×10^{-9} \;\;c\;\;\;\;\;\;-D\]
\[q= 1.78×10^{-9} \;\;c\;\;\;\;\;\;-B\]
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23


A solid non-conducting sphere is uniformly charged with radius
\[R=0.5\;\; m\]. The field at a point \[r=0.3\;\; m\] from the center of the sphere was calculated to be \[E=4×10^3\frac{N}{C}\]. The charge of the sphere is equivalent to:

\[q= 3.54×10^{-6} \;\;c\;\;\;\;\;\;-C\]
\[ q= 5.71×10^{-6} \;\;c\;\;\;\;\;\;-A\]
\[q= 1.85×10^{-6} \;\;c\;\;\;\;\;\;-D\]
\[q= 6.28×10^{-6} \;\;c\;\;\;\;\;\;-B\]
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24


A spherical shell has a charge of
\[-7 \;\;µc \], inner radius
\[2 \;\;m\] and outer radius
\[4\;\;M\]. The electric field at a point was calculated to be
\[E= 3 ×10^3\;\;N/C\] and directed towards the shell. The charge inside the spherical shell is equivalent to:

\[q= +1.67 ×10^{-6} \;\;c\;\;\;\;\;\;-C\]
\[ q= +5.33 ×10^{-6} \;\;c\;\;\;\;\;\;-A\]
\[q= -1.67×10^{-6} \;\;c\;\;\;\;\;\;-D\]
\[q= -5.33×10^{-6} \;\;c\;\;\;\;\;\;-B\]
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25

An electric charge
generates an electric field around it. The electric field at point
\[A\] was calculated to be \[ E= 6×10^4\;\;N/C \]. The electric field at point
\[B\] was calculated to be
\[ E= 3×10^4\;\;N/C \]. The ratio between the distances
\[\frac{r_A}{r_B}\] is equal to:

\[\frac{r_A}{r_B}=0.5\;\;\;\;\;\;-C\]
\[\frac{r_A}{r_B}=0.4\;\;\;\;\;\;-A\]
\[\frac{r_A}{r_B}=0.25\;\;\;\;\;\;-D\]
\[\frac{r_A}{r_B}=0.7\;\;\;\;\;\;-B\]
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26
In the figure below, a point charge generates an electric field around it. The ratio between the field at point
\[A\] to the field at point
\[B\]
is equal to:

\[\frac{E_A}{E_B}=9\;\;\;\;\;\;-C\]
\[\frac{E_A}{E_B}=4\;\;\;\;\;\;-A\]
\[\frac{E_A}{E_B}=16\;\;\;\;\;\;-D\]
\[\frac{E_A}{E_B}=3\;\;\;\;\;\;-B\]
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27
The figure shows four Gaussian surfaces surrounding charge distributions. Which Gaussian surface has no electric flux through it?

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28
A Gaussian surface shaped like a bean is placed in four different regions of an electric field. This is illustrated by the field lines below.

In which case is the total electric flux through the closed surface the highest?
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29
A positive point charge (+4q)
and a negative point charge (-3q) are placed inside a conducting sphere
and a negative point charge is placed outside the sphere
with magnitude
One of the following answers
correctly represents the results of Gauss's law

Both charges affect with the same -C
force but in opposite directions
The charge inside the conductor -A
affects with a greater force on
the charge outside the conductor
The charge inside the conductor will -D
not be affected by a force and the charge
outside the conductor is affected by a force
The charge outside the conductor -B
affects with a greater force on
the charge inside the conductor
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30
(∅=3 ×102N.m2/c ) A charge was placed inside a spherical surface and the flux
on the surface was calculated to be
If the radius of the spherical surface is doubled, the flux on the new surface
becomes

\[∅= 6 ×10^2 \;\;N.m^2/C\;\;\;\;\;\;-C\]
\[ ∅= 12 ×10^2 \;\;N.m^2/C\;\;\;\;\;\;-A\]
\[∅= 3 ×10^2 \;\;N.m^2/C\;\;\;\;\;\;-D\]
\[∅= 1.5×10^2 \;\;N.m^2/C\;\;\;\;\;\;-B\]
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31

An electric field with intensity given by the relation \[E=8\hat{X}+3\hat{Y}+4\hat{Z}(\frac{N.m^2}{c})\]
(10 cm) The flux through the right side surface of a cube with edge length
equals
\[∅= 6 ×10^{-2} \;\;N.m^2/C\;\;\;\;\;\;-C\]
\[ ∅= 8 ×10^{-2 }\;\;N.m^2/C\;\;\;\;\;\;-A\]
\[∅= 2 ×10^{-2} \;\;N.m^2/C\;\;\;\;\;\;-D\]
\[∅= 4×10^{-2} \;\;N.m^2/C\;\;\;\;\;\;-B\]
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32
A hollow conducting sphere with radius \[0.2\;\;m\] was uniformly charged, losing a number of electrons equal to \[n= 5×10^{12}\] electrons. The charge density on the conductor's surface equals:
Given that \[q_e=1.6×10^{-19} c\]

\[𝛿= 1.6 ×10^{-6} \;\;c/m^2\;\;\;\;\;\;-C\]
\[𝛿= 4.8 ×10^{-6} \;\;c/m^2\;\;\;\;\;\;-A\]
\[𝛿= 3.6 ×10^{-6} \;\;c/m^2\;\;\;\;\;\;-D\]
\[𝛿= 6 ×10^{-6} \;\;c/m^2\;\;\;\;\;\;-B\]
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33
A semi-cylinder made of insulating material with small base radius (0.1 m) and large base radius (0.2 m) was placed in a uniform electric field as shown in the figure below with intensity \[500\;\;N/C\]. The flux passing through the lateral surface of the semi-cylinder equals:

\[∅=47.1 \;\;N.m^2/C\;\;\;\;\;\;-C\]
\[ ∅=0.0 \;\;\;\;\;\;-A\]
\[∅= 25.3\;\;N.m^2/C\;\;\;\;\;\;-D\]
\[∅= - 35.2 \;\;N.m^2/C\;\;\;\;\;\;-B\]
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34
A cube has a point charge at its center with a magnitude of
\[8 ×10^{-9}c\]. The flux through the top and bottom surfaces is equal to
\[ 𝓔_0=8.85 ×10^{-12}C.m/v\]

\[∅= 432 \;\;N.m^2/C\;\;\;\;\;\;-C\]
\[ ∅=151 \;\;N.m^2 \;\;\;\;\;\;-A\]
\[∅= 512\;\;N.m^2/C\;\;\;\;\;\;-D\]
\[∅= - 301 \;\;N.m^2/C\;\;\;\;\;\;-B\]
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Solve the following problems
1

Two point charges on a straight line
each with magnitude \[q_1=8\;\;nc\;\;\;\;\;\;\;\;\;\; q_2=?\]The electric field was calculated at point
\[A\] and its magnitude was
\[E_{net}=500 \;\;N/C\]From the figure information and previous data
What is the type of \[q_2\]
\[........................................................................................\]
\[........................................................................................\]
\[........................................................................................\]
Calculate the magnitude of charge \[q_2\]
\[........................................................................................\]
\[........................................................................................\]
\[........................................................................................\]
\[........................................................................................\]
\[........................................................................................\]
One of the following measurement units is equivalent to the electric field measurement unit
\[Kg.m.A^{-1}.s^{-2}\;\;\;\;\;\;-C\] |
\[Kg.m.A^{-1}.s^{-3}\;\;\;\;\;\;-A\] |
\[Kg.m.A^{-1}.s^{-1}\;\;\;\;\;\;-D\] |
\[Kg.m.A^{-2}.s^{-2}\;\;\;\;\;\;-B\] |
Choose the correct answer
An electric field with intensity \[E=500\frac{N}{C}\] has an electron placed inside it. The electric force acting on the electron equals: \[q_e=1.6×10^{-19}C\]

\[Fe=4×10^{-17} \;\;N\;\;\;\;\;\;-C\] Opposite to the field direction |
\[Fe=4×10^{-17} \;\;N\;\;\;\;\;\;-A\] In the field direction |
\[Fe=8×10^{-17} \;\;N\;\;\;\;\;\;-D\] Opposite to the field direction |
\[Fe=8×10^{-17} \;\;N\;\;\;\;\;\;-B\] In the field direction |
Choose the correct answer
In the figure below, two charges are on the same line \[q_1=+9\;\;nc\;\;\;\;\;\;\;\;q_2=?\] At point \[A\]
the electric field is canceled. The magnitude and type of charge
\[q_2\] equals
\[q_2= - 3.2 ×10^{-7}\;\;c\;\;\;\;\;\;-C\] |
\[q_2= + 1.44 ×10^{-7}\;\;c\;\;\;\;\;\;-A\] |
\[q_2= -4.5 ×10^{-7}\;\;c;\;\;\;\;\;-D\] |
\[q_2= + 2.25 ×10^{-7}\;\;c\;\;\;\;\;\;-B\] |
Choose the correct answer
In the figure below, the field at point \[A\] was calculated
\[E_{net}=500\frac{N}{C}\]
and its direction is shown in the drawing. If the magnitude of the electric field
produced by the first charge equals
\[E_{1}=300\frac{N}{C}\]then the type
and magnitude of the second charge equals
\[q_2= - 3.24 ×10^{-9}\;\;c\;\;\;\;\;\;-C\] |
\[q_2= - 2.43 ×10^{-9}\;\;c\;\;\;\;\;\;-A\] |
\[q_2= + 1.78 ×10^{-9}\;\;c;\;\;\;\;\;-D\] |
\[q_2= + 5.67 ×10^{-9}\;\;c\;\;\;\;\;\;-B\] |
Choose the correct answer
In the figure below, the field lines for three charges are drawn.
One of the following answers is correct
\[q_1(-)\;\;\;\;q_2(+)\;\;\;\;q_3(+) \;\;\;\;\;q_3>q_1>q_2\;\;\;\;\;\;-C\] |
\[q_1(+)\;\;\;\;q_2(-)\;\;\;\;q_3(-)\;\;\;\;\;q_1=q_2=q_3\;\;\;\;\;\;-A\] |
\[q_1(+)\;\;\;\;q_2(-)\;\;\;\;q_3(-) \;\;\;\;\;q_1>q_2=q_3\;\;\;\;\;\;-D\] |
\[q_1(+)\;\;\;\;q_2(-)\;\;\;\;q_3(-)\;\;\;\;\;q_2>q_1>q_3\;\;\;\;\;\;-B\] |
Choose the correct answer
(1 ×10-10m ) A dipole with distance between its poles
( 0.4 m ) The field produced by the dipole was calculated at a point distant from the center of the dipole and along the dipole axis
The field intensity was \[E= 9×10^{-18}\frac{N}{C}\]then the dipole charge equals
\[q= 3.2 ×10^{-19}\;\;c\;\;\;\;\;\;-C\] |
\[q= 2.6 ×10^{-19}\;\;c\;\;\;\;\;\;-A\] |
\[q= 1.3 ×10^{-19}\;\;c;\;\;\;\;\;-D\] |
\[q= 6.4 ×10^{-19}\;\;c\;\;\;\;\;\;-B\] |
Choose the correct answer
Choose the correct answer
A positively charged particle is placed inside the field shown in the figure below. One of the following answers represents the motion of the particle:
The particle moves with - C
|
The particle moves with - A
|
The particle moves with - D
|
The particle moves with - B
|
Choose the correct answer

A ball with mass (5g) is dropped to the ground while charged with a charge of (5 µc). The uniform electric field vector that makes it balanced is:
\[E= 1×10^3 \;\;N/C\;\;\;\;\downarrow\;\;\;\;\;\;-C\] Downward |
\[E= 9.8×10^3 \;\;N/C\;\;\;\;\downarrow\;\;\;\;\;\;-A\] Downward |
\[E= 1×10^3 \;\;N/C\;\;\;\;\uparrow\;\;\;\;\;\;-D\] Upward |
\[E= 9.8×10^3 \;\;N/C\;\;\;\;\uparrow\;\;\;\;\;\;-B\] Upward |
Choose the correct answer

An electron is projected into a uniform electric field with intensity (E= 1 × 103N/C)
directed towards the positive vertical axis as shown in the figure below
with a speed of (𝜗=5 × 106m/s) horizontally
and travels a horizontal distance of (8 cm).
In the same time period, it will have a vertical displacement of:
\[ ∆𝑌= 0.011 \;\;m\;\;\;\;\;\;-C\] |
\[ ∆𝑌= 0.033 \;\;m\;\;\;\;\;\;-A\] |
\[ ∆𝑌= 0.044 \;\;m\;\;\;\;\;\;-D\] |
\[ ∆𝑌= 0.022\;\;m\;\;\;\;\;\;-B\] |
Choose the correct answer
One of the following shapes has zero torque for an electric dipole in a uniform electric field
Choose the correct answer
( τ= 1.5 × 10-9N.m ) An electric dipole has maximum torque when
(positive z-axis) and is directed along the
(positive y-axis) in a uniform electric field directed along the
( E = 1 × 10-3N/C ) with magnitude
\[P=1.5×10^{-6} \;\;c.m\;\;\;\;\;\;-C\] along the positive horizontal axis |
\[ P=1.5×10^{-8} \;\;c.m\;\;\;\;\;\;-A\] along the positive horizontal axis |
\[P=1.5×10^{-8} \;\;c.m\;\;\;\;\;\;-D\] along the negative horizontal axis |
\[P=1.5×10^{-6} \;\;c.m\;\;\;\;\;\;-B\] along the negative horizontal axis |
Choose the correct answer

(0.3 m) An infinite wire has an electric field calculated at a point
( 2.5 × 103N/C ) The electric field magnitude was
and direction is shown in the figure. The number of electrons gained or lost per unit length equals
\[n=2.6×10^{11}\;\;\;\;\;\;-C\] Gained electrons |
\[ n=2.6×10^{11} \;\;\;\;\;\;-A\] Lost electrons |
\[n=3.4×10^{11}\;\;\;\;\;\;-D\] Gained electrons |
\[n=3.4×10^{11}\;\;\;\;\;\;-B\] Lost electrons |
Choose the correct answer

One of the following units is a unit of electric flux
\[Kg.m .A^{-1}.S^{-3}\;\;\;\;\;\;-C\] |
\[Kg.m^2 .A^{-1}.S^{-3}\;\;\;\;\;\;-A\] |
\[Kg.m^3 .A^{-1}.S^{-3}\;\;\;\;\;\;-D\] |
\[Kg.m^2 .A^{-1}.S^{-2}\;\;\;\;\;\;-B\] |
Choose the correct answer
A spherical shell is charged with a charge of \[-4\;\;µc\] and a charge is placed inside it \[+4\;\;µc\]>then the internal charge \[q_1=?\] and external charge of the spherical shell \[q_2=?\] respectively
\[q_1=+4\;µc \;\;\;\;\;q_2=+4\;µc\;\;\;\;\;\;-C\] |
\[q_1=0.0 \;\;\;\;\;q_2=0.0\;\;\;\;\;\;-A\] |
\[q_1=-4\;µc \;\;\;\;\;q_2=0.0\;\;\;\;\;\;-D\] |
\[q_1=-4\;µc \;\;\;\;\;q_2=+4\;µc\;\;\;\;\;\;-B\] |
Choose the correct answer

( A ) Two infinite wires in length with charge densities and dimensions shown in the figure below. The point has a field intensity equal to
\[ E= 4200 \;\;N/C\;\;\;\;\;\longrightarrow\;\;\;\;\;\;-C\] To the right |
\[ E= 2800 \;\;N/C\;\;\;\;\;\longleftarrow \;\;\;\;\;\;-A\] To the left |
\[E= 4800 \;\;N/C\;\;\;\;\;\longrightarrow\;\;\;\;\;\;-D\] To the right |
\[E= 3500 \;\;N/C\;\;\;\;\;\longleftarrow\;\;\;\;\;\;-B\] To the left |
Choose the correct answer
Two infinite parallel conducting plates charged with equal charge density.
One of the following answers is correct:
\[ EA=EB=EC=ED \;\;\;\;\;\;-C\] |
\[EA=EC=0 \;\;\;\;\;, \;\;\;\;\;EB=ED≠0\;\;\;\;\;\;-A\] |
\[ EA=EB \;\;\;\;\;, \;\;\;\;\;ED=EC\;\;\;\;\;\;-D\] |
\[EA>EC \;\;\;\;\;, \;\;\;\;\;EB=ED \;\;\;\;\;\;-B\] |
Choose the correct answer

Two infinite unconnected plates with the same charge. The electric field at point A was calculated to be \[E= 1×10^3\frac{N}{C}\]. The charge density on each plate is:
\[𝛿= 3.6 ×10^{-9} \;\;c/m^2\;\;\;\;\;\;-C\] |
\[𝛿= 3.9×10^{-8} \;\;c/m^2\;\;\;\;\;\;-A\] |
\[𝛿= 4.8×10^{-9} \;\;c/m^2\;\;\;\;\;\;-D\] |
\[𝛿= 8.85×10^{-9} \;\;c/m^2\;\;\;\;\;\;-B\] |
Choose the correct answer

Two infinite unconnected plates with the same charge. The electric field at point A was calculated to be \[E= 1×10^3\frac{N}{C}\]. The charge density on each plate is:
\[𝛿= 3.6 ×10^{-9} \;\;c/m^2\;\;\;\;\;\;-C\] |
\[𝛿= 3.9×10^{-8} \;\;c/m^2\;\;\;\;\;\;-A\] |
\[𝛿= 4.8×10^{-9} \;\;c/m^2\;\;\;\;\;\;-D\] |
\[𝛿= 8.85×10^{-9} \;\;c/m^2\;\;\;\;\;\;-B\] |
Choose the correct answer

An infinite conducting plate with a charge density of
\[6 × 10^{-6} \;\;C/m^2\] was left.
A positively charged sphere with a charge of
\[+4\;\;nc\] and a mass of
\[9 \;\;g\] falls towards the plate.
The sphere moves with an acceleration of
\[ a=6.37 \;\;m/s^2\;\;\;\;\;\uparrow \;\;\;\;\;\;-C\] Upwards |
\[ a=3.92 \;\;m/s^2\;\;\;\;\;\uparrow \;\;\;\;\;\;-A\] Upwards |
\[a=4.52 \;\;m/s^2\;\;\;\;\;\downarrow \;\;\;\;\;\;-D\] Downwards |
\[a=9.48 \;\;m/s^2\;\;\;\;\;\downarrow \;\;\;\;\;\;-B\] Downwards |
Choose the correct answer


An uncharged spherical shell with an inner radius
\[0.5\;] and an outer radius
\[0.7\; m\] A point charge was placed inside it as shown in the figure below with a magnitude of
\[-6\;µc \] at its center. The electric field intensity at a point located at a distance of
\[0.6\; m \]
\[ E=0.0\;\;\;\;\;\;-C\] |
\[ E = 2.3 ×10^5 \;\;N/C \;\;\;\;\;\;-A\] |
\[ E = 1.5 ×10^5 \;\;N/C\;\;\;\;\;\;-D\] |
\[ E = 4.6 ×10^5 \;\;N/C\;\;\;\;\;\;-B\] |
Choose the correct answer

The relationship between the electric field and the distance from the surface of a hollow conducting sphere was plotted, resulting in the following graph. The conductor is charged with a charge of
\[q= 1.34×10^{-19} \;\;c\;\;\;\;\;\;-C\] |
\[ q= 2.56×10^{-19} \;\;c\;\;\;\;\;\;-A\] |
\[q= 2.14×10^{-19} \;\;c\;\;\;\;\;\;-D\] |
\[q= 1.78×10^{-19} \;\;c\;\;\;\;\;\;-B\] |
Choose the correct answer


The relationship between the electric field and the distance from the center of a charged sphere
with a non-conducting solid was plotted, resulting in the following graph. The magnitude of the electric field at
a point located at a distance
\[0.15\;m\] from the center of the sphere is equivalent to
\[E=2800 \;\;N/C\;\;\;\;\;\;-C\] |
\[E=3000 \;\;N/C\;\;\;\;\;\;-A\] |
\[E=2700 \;\;N/C\;\;\;\;\;\;-D\] |
\[E=2900 \;\;N/C\;\;\;\;\;\;-B\] |
Choose the correct answer


The relationship between the electric field and distance from the center
of a uniformly charged solid non-conducting sphere was plotted,
resulting in the following graph.
The amount of charge contained within a radius of
\[0.1\;m\]
of the sphere is equivalent to:
\[q= 2.2×10^{-9} \;\;c\;\;\;\;\;\;-C\] |
\[ q= 2.45×10^{-9} \;\;c\;\;\;\;\;\;-A\] |
\[q= 7.45×10^{-9} \;\;c\;\;\;\;\;\;-D\] |
\[q= 1.78×10^{-9} \;\;c\;\;\;\;\;\;-B\] |
Choose the correct answer


A solid non-conducting sphere is uniformly charged with radius
\[R=0.5\;\; m\]. The field at a point \[r=0.3\;\; m\] from the center of the sphere was calculated to be \[E=4×10^3\frac{N}{C}\]. The charge of the sphere is equivalent to:
\[q= 3.54×10^{-6} \;\;c\;\;\;\;\;\;-C\] |
\[ q= 5.71×10^{-6} \;\;c\;\;\;\;\;\;-A\] |
\[q= 1.85×10^{-6} \;\;c\;\;\;\;\;\;-D\] |
\[q= 6.28×10^{-6} \;\;c\;\;\;\;\;\;-B\] |
Choose the correct answer


A spherical shell has a charge of \[-7 \;\;µc \], inner radius \[2 \;\;m\] and outer radius \[4\;\;M\]. The electric field at a point was calculated to be \[E= 3 ×10^3\;\;N/C\] and directed towards the shell. The charge inside the spherical shell is equivalent to:
\[q= +1.67 ×10^{-6} \;\;c\;\;\;\;\;\;-C\] |
\[ q= +5.33 ×10^{-6} \;\;c\;\;\;\;\;\;-A\] |
\[q= -1.67×10^{-6} \;\;c\;\;\;\;\;\;-D\] |
\[q= -5.33×10^{-6} \;\;c\;\;\;\;\;\;-B\] |
Choose the correct answer

An electric charge
generates an electric field around it. The electric field at point
\[A\] was calculated to be \[ E= 6×10^4\;\;N/C \]. The electric field at point
\[B\] was calculated to be
\[ E= 3×10^4\;\;N/C \]. The ratio between the distances
\[\frac{r_A}{r_B}\] is equal to:
\[\frac{r_A}{r_B}=0.5\;\;\;\;\;\;-C\] |
\[\frac{r_A}{r_B}=0.4\;\;\;\;\;\;-A\] |
\[\frac{r_A}{r_B}=0.25\;\;\;\;\;\;-D\] |
\[\frac{r_A}{r_B}=0.7\;\;\;\;\;\;-B\] |
Choose the correct answer
In the figure below, a point charge generates an electric field around it. The ratio between the field at point
\[A\] to the field at point
\[B\]
is equal to:
\[\frac{E_A}{E_B}=9\;\;\;\;\;\;-C\] |
\[\frac{E_A}{E_B}=4\;\;\;\;\;\;-A\] |
\[\frac{E_A}{E_B}=16\;\;\;\;\;\;-D\] |
\[\frac{E_A}{E_B}=3\;\;\;\;\;\;-B\] |
Choose the correct answer
The figure shows four Gaussian surfaces surrounding charge distributions. Which Gaussian surface has no electric flux through it?
Choose the correct answer
A Gaussian surface shaped like a bean is placed in four different regions of an electric field. This is illustrated by the field lines below.
In which case is the total electric flux through the closed surface the highest?
Choose the correct answer
A positive point charge (+4q)
and a negative point charge (-3q) are placed inside a conducting sphere
and a negative point charge is placed outside the sphere
with magnitude
One of the following answers
correctly represents the results of Gauss's law
Both charges affect with the same -C
|
The charge inside the conductor -A
|
The charge inside the conductor will -D
|
The charge outside the conductor -B
|
Choose the correct answer
(∅=3 ×102N.m2/c ) A charge was placed inside a spherical surface and the flux
on the surface was calculated to be
If the radius of the spherical surface is doubled, the flux on the new surface
becomes
\[∅= 6 ×10^2 \;\;N.m^2/C\;\;\;\;\;\;-C\] |
\[ ∅= 12 ×10^2 \;\;N.m^2/C\;\;\;\;\;\;-A\] |
\[∅= 3 ×10^2 \;\;N.m^2/C\;\;\;\;\;\;-D\] |
\[∅= 1.5×10^2 \;\;N.m^2/C\;\;\;\;\;\;-B\] |
Choose the correct answer

An electric field with intensity given by the relation \[E=8\hat{X}+3\hat{Y}+4\hat{Z}(\frac{N.m^2}{c})\]
(10 cm) The flux through the right side surface of a cube with edge length
equals
\[∅= 6 ×10^{-2} \;\;N.m^2/C\;\;\;\;\;\;-C\] |
\[ ∅= 8 ×10^{-2 }\;\;N.m^2/C\;\;\;\;\;\;-A\] |
\[∅= 2 ×10^{-2} \;\;N.m^2/C\;\;\;\;\;\;-D\] |
\[∅= 4×10^{-2} \;\;N.m^2/C\;\;\;\;\;\;-B\] |
Choose the correct answer
A hollow conducting sphere with radius \[0.2\;\;m\] was uniformly charged, losing a number of electrons equal to \[n= 5×10^{12}\] electrons. The charge density on the conductor's surface equals:
Given that \[q_e=1.6×10^{-19} c\]

\[𝛿= 1.6 ×10^{-6} \;\;c/m^2\;\;\;\;\;\;-C\] |
\[𝛿= 4.8 ×10^{-6} \;\;c/m^2\;\;\;\;\;\;-A\] |
\[𝛿= 3.6 ×10^{-6} \;\;c/m^2\;\;\;\;\;\;-D\] |
\[𝛿= 6 ×10^{-6} \;\;c/m^2\;\;\;\;\;\;-B\] |
Choose the correct answer
A semi-cylinder made of insulating material with small base radius (0.1 m) and large base radius (0.2 m) was placed in a uniform electric field as shown in the figure below with intensity \[500\;\;N/C\]. The flux passing through the lateral surface of the semi-cylinder equals:
\[∅=47.1 \;\;N.m^2/C\;\;\;\;\;\;-C\] |
\[ ∅=0.0 \;\;\;\;\;\;-A\] |
\[∅= 25.3\;\;N.m^2/C\;\;\;\;\;\;-D\] |
\[∅= - 35.2 \;\;N.m^2/C\;\;\;\;\;\;-B\] |
Choose the correct answer
A cube has a point charge at its center with a magnitude of
\[8 ×10^{-9}c\]. The flux through the top and bottom surfaces is equal to
\[ 𝓔_0=8.85 ×10^{-12}C.m/v\]
\[∅= 432 \;\;N.m^2/C\;\;\;\;\;\;-C\] |
\[ ∅=151 \;\;N.m^2 \;\;\;\;\;\;-A\] |
\[∅= 512\;\;N.m^2/C\;\;\;\;\;\;-D\] |
\[∅= - 301 \;\;N.m^2/C\;\;\;\;\;\;-B\] |
Choose the correct answer
Solve the following problems

Two point charges on a straight line each with magnitude \[q_1=8\;\;nc\;\;\;\;\;\;\;\;\;\; q_2=?\]The electric field was calculated at point \[A\] and its magnitude was \[E_{net}=500 \;\;N/C\]From the figure information and previous data What is the type of \[q_2\]
Physics